How much additional altitude can rocket obtain with launch assist.

AI Thread Summary
The discussion focuses on calculating the altitude achieved by a model rocket launched with an assist from a rubber band system. The first rocket reaches 1000 feet at launch speed of 0 ft/sec, while the second rocket is launched at 150 ft/sec before ignition. Participants suggest using kinematic equations to determine the additional altitude gained by the second rocket and discuss the significance of initial speed on rocket performance. One participant estimates the total altitude of the second rocket to be 2147 feet, factoring in the additional height from the launch assist. The conversation emphasizes the importance of understanding momentum and velocity in rocket flight dynamics.
Futabo
Messages
1
Reaction score
0

Homework Statement


We have 2 model rockets identical in all ways (weight, height, mass, propellant, etc). The first rocket is launched like most rockets (0 ft/sec) and reaches 1000ft. For the second rocket we use a SUPER rubberband launch system. The launch system sends the rocket to say, 150 ft/sec before the rocket ignites. What altitude will the 2nd rocket reach? Please see the attached image.


Homework Equations


I assume part of it involves Kinematic Equations. Something like V² = U² +2*a*s. After that do we just add together 1000+the result? Or is it far more complex? I heard that rockets perform better at speed. In theory, are the gains in altitude significant? The plan is to do a real world test! My profession is in advertising and have loved rockets since childhood, but physics is way over my head!


The Attempt at a Solution


1000 + 1147 = 2147
BAM! How's that?
 

Attachments

  • RocketQuestion.gif
    RocketQuestion.gif
    54 KB · Views: 605
Physics news on Phys.org
Futabo said:

Homework Statement


We have 2 model rockets identical in all ways (weight, height, mass, propellant, etc). The first rocket is launched like most rockets (0 ft/sec) and reaches 1000ft. For the second rocket we use a SUPER rubberband launch system. The launch system sends the rocket to say, 150 ft/sec before the rocket ignites. What altitude will the 2nd rocket reach? Please see the attached image.


Homework Equations


I assume part of it involves Kinematic Equations. Something like V² = U² +2*a*s. After that do we just add together 1000+the result? Or is it far more complex? I heard that rockets perform better at speed. In theory, are the gains in altitude significant? The plan is to do a real world test! My profession is in advertising and have loved rockets since childhood, but physics is way over my head!


The Attempt at a Solution


1000 + 1147 = 2147
BAM! How's that?

A rocket burns fro a specific time - applying a calculatable impulse and thus increase in momentum. One the fuel runs out the rocket will be traveling at high speed, so continues [slowing down] until it stops rising, and returns to Earth.

I would draw Velocity time graphs of the two flights - it becomes [should anyway] clear from there.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top