How Much Can a School Earn from a $50000 Donation Invested for 3 Years?

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SUMMARY

An alumnus donated $50,000 to a local high school, which was invested for 3 years at an annual interest rate of 7.75%, compounded quarterly. Using the accumulation formula P·(1 + i/m)^(n·m), the total interest earned at the end of the investment term was calculated through quarterly compounding. After 12 quarters, the school will have approximately $6,000 available for purchasing sports equipment, derived from the interest earned on the initial investment.

PREREQUISITES
  • Understanding of compound interest and accumulation formulas
  • Familiarity with financial mathematics concepts
  • Basic knowledge of quarterly compounding
  • Ability to perform calculations involving percentages and interest rates
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  • Study the derivation and application of the compound interest formula
  • Learn about different compounding frequencies and their effects on investment growth
  • Explore financial planning strategies for educational institutions
  • Investigate investment options for non-profit organizations
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Finance students, school administrators, and anyone involved in managing donations and investments for educational institutions will benefit from this discussion.

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An alumnus of a local high school donated $50000 to the school. The amount was invested for 3 years at 7.75%, compounded quarterly. The school has agreed to use only the interest earned on the investment to buy sports equipment. How much money will be available for sports equipment at the end of the investments term?
 
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kellyblaack said:
An alumnus of a local high school donated $50000 to the school. The amount was invested for 3 years at 7.75%, compounded quarterly. The school has agreed to use only the interest earned on the investment to buy sports equipment. How much money will be available for sports equipment at the end of the investments term?

It is very important to have basic accumulation formulas in your pocket. Memorize this one!

P\cdot \left(1 + \dfrac{i}{m}\right)^{n\cdot m} -- This gives the accumulated value.

P is the beginning principle balance.
i is the constant nominal annual interest rate.
m is the number of compounding periods in a single year.
n is the number of years to accumulate.
By extension, n * m is the number of compounding periods in the entire accumulation period.

Let's see if this leads you to answering the question. :-)
 
Three years has only 12 quarters so it is not that hard to do it "by hand".

For the first quarter, 50000 was invested at .0775/4= 0.019375. That earned (0.019375)(50000)= 968.75 interest. There is now 50968.75 in the account.

For the second quarter, 50968.75 was invested at 0.019375. That earned (0.19375)(50968.75)= 987.52 interest. There is now 51956.27 in the account.

Continue that for 10 more quarters to find the total amount in the account at the end f the three years. Subtract the original 50000 from the total amount to find the total interest earned.
 

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