How much energy do we need to vapourize 1 liter of water?

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To vaporize 1 liter of water starting at 0 degrees Celsius, a total of 2680 kJ is required, which includes heating the water to 100 degrees Celsius and the latent heat of vaporization. The formula used is Q = mcΔT + mlv, where m is mass, c is specific heat, ΔT is the temperature change, and lv is the latent heat of vaporization. If further heating of the steam is desired, additional energy must be calculated based on the specific heat of steam. Vaporization can occur at various temperatures, requiring different amounts of heat. For precise calculations, utilizing a steam table is recommended.
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How much energy do we need to vapourize 1 liter of water?

How much energy do we need to vapourize 1 liter of water?

I know that to heat up 1liter of water by 1 degree, you need 1kcal(or 4,2kj/kgK).
So let us say that th water is 0 degree at start temperature, and that the boiling temperature is 100 degree.
So is the answear then: 4,2*100=420KJ ??
 
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That gets the water to 100C but not vaporized. For that you need to add in waters heat of vaporization. (you can do a web search to find that number.)
 


If you are starting as liquid water at 0 degrees C, then the total energy needed would be the energy to increase the temperature from 0 deg C to 100 deg C + the energy required to change the phase of the water from liquid to gas (latent heat)

Q= mcΔT + mlv where lv is the latent heat of vaporization of water.
 


Thanks...
Q= mcΔT + mlv is just for steam at 100 degrees ? So if I want the steam to increase in temperature I need to add more energy right ??
But how is the equation if want the steam to be 200 degrees?
 
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rock.freak667 said:
If you are starting as liquid water at 0 degrees C, then the total energy needed would be the energy to increase the temperature from 0 deg C to 100 deg C + the energy required to change the phase of the water from liquid to gas (latent heat)

Q= mcΔT + mlv where lv is the latent heat of vaporization of water.

To get 1kg of water at 0 degrees to steam at 100degrees you need:
(1Kg*4,2KJ/KgK*100K)+(1Kg*2260KJ/Kg)=2680KJ, right?
 


That's only if the water is vaporized at 100C. Of course, it can also be vaporized at all other temperature, up to the critical temperature, with different amounts of heat required.
 


To find out how much heat is required to raise the temperature of 100C steam to 200C, you'll have to find out the specific heat of steam.

A more practical approach is to use a steam table.
 
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