How Much Force is Needed?-Part One.

Thread starter Medgirl314
Start date Jan 9, 2014
Tags

Force

AI Thread Summary

To accelerate a 3.0 gram object at 5000 g's, the required force is calculated using the formula F=ma. The mass is converted to 0.003 kg, and the acceleration is 49033 m/s². The resulting force is 147 Newtons. The calculation is confirmed to be correct, assuming the object's mass is indeed 3 grams. This confirms the accuracy of the force needed for the specified acceleration.

Jan 9, 2014

Medgirl314

Homework Statement

How much force is needed to accelerate a 3.0 object at 5000 g's?

Homework Equations

F=ma

The Attempt at a Solution

I converted units so that I could get an answer in Newtons.
M=0.003 kg
A=49033 m/s^2

F=0.003 kg*49033 m/s^2=147 Newtons.

Could someone please confirm this answer?

Thanks!

Physics news on Phys.org

Jan 9, 2014

haruspex

Science Advisor

Homework Helper

Insights Author

Gold Member

2024 Award

Assuming the object is 3 grams, yes.

Jan 9, 2014

Medgirl314

Oh, yes, it is. Sorry. Thank you!

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »