How Much Force is Needed to Move a Wire with Soapy Solution?

AI Thread Summary
To calculate the force needed to move a wire in a soapy solution, the surface tension (0.025 N/m) and the wire length (16.0 cm or 0.16 m) are used in the formula γ = F/l. The resulting force calculation yields 0.004 N or 4.0 x 10^-3 N. The initial confusion stemmed from visualizing the problem correctly, but clarification helped resolve the issue. Understanding the relationship between surface tension, force, and length is crucial for solving similar problems.
EmilyO89
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1.
Calculate the force needed to move the wire in the figure (Figure 1) if it holds a soapy solution (surface tension is 0.025 N/m) and the wire is 16.0 cm long.

Express your answer to two significant figures and include the appropriate units.

giancoli_cp7.ch10.p67.jpg
2.

γ(surface tension) = F (force) / l (length)

3. My attempt at a solution

γ=F/l so γl=F

γ: 0.025 N/m

l: 16cm or 0.16m

0.025 N/m * 0.16m = 0.004 N or 4.0 * 10-3N

I know this must be ridiculously easy but I really can't figure out what I'm missing here. Do I need another equation to solve this problem? Am I messing up the units somehow?
 
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EmilyO89 said:
1.
Calculate the force needed to move the wire in the figure (Figure 1) if it holds a soapy solution (surface tension is 0.025 N/m) and the wire is 16.0 cm long.

Express your answer to two significant figures and include the appropriate units.

giancoli_cp7.ch10.p67.jpg
2.

γ(surface tension) = F (force) / l (length)

3. My attempt at a solution

γ=F/l so γl=F

γ: 0.025 N/m

l: 16cm or 0.16m

0.025 N/m * 0.16m = 0.004 N or 4.0 * 10-3N

I know this must be ridiculously easy but I really can't figure out what I'm missing here. Do I need another equation to solve this problem? Am I messing up the units somehow?
I can't help at this time, but someone will pretty soon:) I just have time to say welcome to PF and hope you stay around and get to know some people:D
 
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Look very carefully at the second part of the figure.

Chet
 
Chestermiller said:
Look very carefully at the second part of the figure.

Chet

Got it. Thank you!

I knew it must be something simple like that but I was getting hung up because I just could not visualize exactly what this thing is supposed to look like.
 
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