How Much Ice Melts When a Bullet Penetrates It?

  • Thread starter Thread starter BuBbLeS01
  • Start date Start date
  • Tags Tags
    Ice
AI Thread Summary
A 70 gram bullet traveling at 250 m/s impacts a block of ice at 0 degrees Celsius, and the goal is to determine how much ice melts from this collision. To solve this, one must calculate the kinetic energy of the bullet and the energy required to melt ice. The kinetic energy of the bullet can be calculated using the formula KE = 0.5 * mass * velocity^2. The energy needed to melt ice is based on its latent heat of fusion, which is approximately 334 joules per gram. Understanding these energy transfers is crucial to finding the amount of ice melted by the bullet's impact.
BuBbLeS01
Messages
602
Reaction score
0
Please help...How much ice melts?

Homework Statement


A 70 gram bullet traveling at 250 m/s penetrates a block of ice at 0 degrees Celsius and comes to rest within the ice. Assuming that the temperature of the bullet doesn't change appreciably, how much ice is melted as a result of the collision?

The Attempt at a Solution


I don't know where to start on this?
 
Physics news on Phys.org
Questions to get you started:

How much energy is needed to melt a gram of ice?

How much energy does the bullet give to the block of ice when it slows down?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

The Mystery of Heat Loss: Examining Ice Melting Without Heat Loss
Replies
11
Views
2K
How much ice to cool down this water?
Replies
17
Views
5K
Thermodynamics, bullet melting ice problem
Replies
4
Views
2K
Heat transfer, how long it takes ice to reach melting point
Replies
6
Views
4K
Ice melted by impact of lead bullet
Replies
10
Views
3K
Thermodynamics Ice Melting Question
Replies
4
Views
3K
Piece of iron put into container with ice
Replies
4
Views
1K
Calculating Friction & Time for a Bullet Penetrating Rubber
Replies
2
Views
1K
Final temperature after pouring soda into glass with ice....
Replies
5
Views
6K
Final Temperature and Time to Reach it When Adding Ice to Rum and Coke
Replies
12
Views
2K

Hot Threads

Recent Insights

Back
Top