How Much Ice Was Added to Cool the Lemonade?

[chops369]

Homework Statement

How much ice was added to a 0.75 kg jug of lemonade at 15 degrees celcius if the final temperature of the jug is 8 degrees celcius? (Assume the lemonade has the specific heat capacity of water.)

Homework Equations

Q = cm∆T

The Attempt at a Solution

Well I think I might have to rearrange Q = cm∆T to solve for mass, so m = Q/c*∆T. But I don't have the heat, and then how would I account for the mass of the jug? Help!

 

[mgb_phys]

You don't need the mass of the jug - it means the final temperautre of the mixture in the jug.
Remember the energy needed to melt ice.

 

[chops369]

So you're saying I need to use latent heat? If that's the case then I would use Q = cm∆T + mLv, right?

 

[mgb_phys]

So you're saying I need to use latent heat? If that's the case then I would use Q = cm∆T + mLv, right?

Yes, and that equals the Q = cm∆T lost by the warm lemonade to get to the final temperature.