How Much Iodine Reacts with 23 Grams of Aluminum?

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Discussion Overview

The discussion revolves around calculating the mass of iodine (I2) that reacts with 23 grams of aluminum (Al) to form aluminum iodide (AlI3). It involves stoichiometric calculations based on a chemical reaction.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to begin the calculation.
  • Another participant suggests writing the balanced chemical reaction and using mole ratios to find the required quantities.
  • A participant provides a balanced reaction: 3I2 + 2Al → 2AlI3, and lists various mass and mole values but seems unsure about the next steps.
  • A later reply emphasizes the importance of mole ratios and asks for the formula weight of aluminum, the moles of aluminum present, and the corresponding moles and grams of iodine needed.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the next steps for the calculation, and there is ongoing uncertainty about the process.

Contextual Notes

Participants have not provided specific values for the molar masses or completed the stoichiometric calculations, which may affect the clarity of the discussion.

Who May Find This Useful

Students or individuals interested in stoichiometry and chemical reactions, particularly in the context of homework or academic exercises.

mightyhealthy
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Homework Statement


Calculate the mass in grams of iodine(I2) that will react completely with 23g of aluminum (Al) to form aluminum iodide (AlI3).


Homework Equations





The Attempt at a Solution



don't even know where to start

mol mol avogrado mol
 
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Write the reaction to start. Next, use the information in the PROPERLY BALANCED reaction to find mole ratios. Do the rest.
 
symbolipoint said:
Write the reaction to start. Next, use the information in the PROPERLY BALANCED reaction to find mole ratios. Do the rest.

ok I've had this for a day:

3I2+2Al---->2AlI3


761.4g
3 mol

53.96g
2 mol

815.36g
2 mol

now what?
 
Nice Reaction Notation. Now, pay attention to the MOLE RATIOS indicated in that reaction. What is the formula weight for Aluminum? You are starting with 23 grams of Aluminum.
How many moles of Aluminum is this?
How many moles of Iodine are needed?
How many grams of Iodine is this?
 

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