How Much Iodine Reacts with 23 Grams of Aluminum?

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To determine the mass of iodine (I2) that reacts with 23 grams of aluminum (Al) to form aluminum iodide (AlI3), the balanced chemical equation 3I2 + 2Al → 2AlI3 is essential. First, calculate the moles of aluminum using its molar mass, which is approximately 26.98 g/mol. Based on the mole ratio from the balanced equation, 2 moles of Al react with 3 moles of I2, allowing for the calculation of the required moles of iodine. Finally, convert the moles of iodine into grams using its molar mass, approximately 253.8 g/mol. This process will yield the total mass of iodine needed for the reaction.
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Homework Statement


Calculate the mass in grams of iodine(I2) that will react completely with 23g of aluminum (Al) to form aluminum iodide (AlI3).


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The Attempt at a Solution



don't even know where to start

mol mol avogrado mol
 
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Write the reaction to start. Next, use the information in the PROPERLY BALANCED reaction to find mole ratios. Do the rest.
 
symbolipoint said:
Write the reaction to start. Next, use the information in the PROPERLY BALANCED reaction to find mole ratios. Do the rest.

ok I've had this for a day:

3I2+2Al---->2AlI3


761.4g
3 mol

53.96g
2 mol

815.36g
2 mol

now what?
 
Nice Reaction Notation. Now, pay attention to the MOLE RATIOS indicated in that reaction. What is the formula weight for Aluminum? You are starting with 23 grams of Aluminum.
How many moles of Aluminum is this?
How many moles of Iodine are needed?
How many grams of Iodine is this?
 

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