How much is the mass of the sun losing every second?

  • Thread starter Thread starter trevorr93
  • Start date Start date
  • Tags Tags
    Mass Sun The sun
AI Thread Summary
The discussion centers on the sun's mass loss and its implications for future generations. The sun outputs approximately 4 x 10^26 Watts, leading to inquiries about how to calculate its mass loss per second. The equation E=mc^2 is identified as a key formula for understanding this relationship. There is uncertainty about whether the sun's power output will remain constant over time. Overall, the conversation highlights concerns about the sun's longevity and its impact on future life on Earth.
trevorr93
Messages
5
Reaction score
0
My friend told me that the sun is going to get smaller and smaller every year because it's getting used up? I've read that the power output is 4 x 10^26 Watts. How can i figure out how much mass it's losing a second? because then I will be able to find how long the sun will be able to shine on me and my children (hopefully).

thanks.

I don't really know how to attempt this problem because it's really random and i don't know any formulas for power.

merci.
 
Physics news on Phys.org
nvm i think E=mc^2 will help me out thanks. wow I don't think my children will live to see the sun. sucks for them i am going to take lots of pictures i guess ..
 
1 watt = 1 joule per second

Mass is converted into energy through the equation

E = mc^2.

But is the power quoted going to remain constant throughout all the time t to be calculated?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Deflection of light passing the Sun
Replies
3
Views
1K
Earth's Acceleration Toward the Sun
Replies
5
Views
7K
Rate at which Sun converts mass to radiation
Replies
14
Views
2K
B Sun's Mass Loss: 4 Billion kg/sec from Sunlight & Ejected Particles
Replies
8
Views
2K
Is this question on Intensity of light from Sun correct?
Replies
3
Views
1K
Effective cross-section of catching a comet with the Sun
Replies
19
Views
2K
Effective cross-section of catching a comet with the Sun
Replies
1
Views
2K
How would I calculate how close a ship can approach the sun?
Replies
4
Views
2K
B How bright is the Sun compared to the sky?
Replies
17
Views
3K
How to find the speed of a planet around the sun
Replies
1
Views
4K

Hot Threads

Recent Insights

Back
Top