How Much Kinetic Energy is Stored in the Spring After a Collision?

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The discussion focuses on calculating the kinetic energy stored in a spring after a collision involving a ball and a spring gun. A 0.25 kg ball traveling at 120 m/s collides with a stationary 1.8 kg spring gun, resulting in an inelastic collision where the ball becomes embedded in the spring. The conservation of momentum is applied to determine the velocity of the combined system at maximum compression. The kinetic energy of the center of mass before the collision is used to find the energy converted into spring potential energy. The analysis concludes that this method effectively reveals the fraction of the ball's initial kinetic energy stored in the spring.
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A ball of mass 0.25 kg is fired with velocity 120 m/s into the barrel of a spring gun of mass 1.8 kg initially at rest on a frictionless surface. The ball sticks in the barrel at the point of maximum compression of the spring. No energy is lost to friction. What fraction of the ball's initial kinetic energy is stored in the spring?
 
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You'll need inelastic collision conservation of momentum:
(m1+m2)V_cen. of mass = m1v1 +m2v2

And a translation into a center of mass reference frame:
v'1 + v_cen. of mass = v1

If you get the kinetic energy of the center of mass of the system before the collision that will be the kinetic energy that was lost into internal spring potential...

Maybe there is an easier way, but I'm pretty sure this will get you the answer.
 
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