How Much Power Is Lost Due to Resistive Heating in a High-Voltage Line?

AI Thread Summary
A 750-MW power plant transmits power through a 475,000 V high-voltage line with a resistance of 0.65 Ω. The discussion revolves around calculating the percentage of power lost due to resistive heating using the formula P(loss) = I²R. The user initially struggled to find the current (I) but successfully used P = VI to determine it, leading to the calculation of power loss. Ultimately, the user was able to compute the power loss and express gratitude for the assistance received. The conversation highlights the importance of understanding resistive heating in high-voltage power transmission.
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Homework Statement


A 750-MW power plant sends its power out on a 475,000 V high-voltage line. If the total resistance of the line is 0.65 Ω, what percentage of the power is lost due to resistive heating?


Homework Equations


i have NO idea but maybe...

P(loss)=I²R

P(loss)=^v²/R

P=V(V/R)

P=VI

V=IR

P=E/t


The Attempt at a Solution



Guess i don't know where to start
 
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Use P=VI to find I.
 
thanks i found I then i was able to get the Ploss=I^2(R)

got the answer Thanks!
 

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