How much tension must a rope withstand if it is used to accelerate a 1500 kg car vertically upward at 0.40 m/s2?

AI Thread Summary
To determine the tension in the rope needed to accelerate a 1500 kg car vertically upward at 0.40 m/s², one must apply the formula for net force, which is Net Force = Mass × Acceleration. Additionally, the weight of the car, calculated as mass times gravitational acceleration (approximately 9.81 m/s²), must be considered. The total tension in the rope will be the sum of the force required to overcome the weight of the car and the force needed for the upward acceleration. This problem is typical in physics coursework, and participants are reminded to adhere to homework guidelines. Understanding these principles is essential for solving similar physics problems effectively.
cgward
Messages
5
Reaction score
0
How much tension must a rope withstand if it is used to accelerate a 1500 kg car vertically upward at 0.40 m/s2?

What is the equation to find the force
 
Physics news on Phys.org
F=ma
force equals mass*acceleration
 
...but don't forget the weight of the car...
 
Actually is more Net Force = Ma
 
cgward said:
How much tension must a rope withstand if it is used to accelerate a 1500 kg car vertically upward at 0.40 m/s2?

What is the equation to find the force
This is a standard textbook question, and the OP should be required to conform to the Homework & Coursework guidelines.

cgward: please read the guidelines (see link in signature, below) for help with standard textbook/homework problems.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Monkey accelerating up and down a rope
Replies
38
Views
4K
Tension in a deformed cylindrical bag on a surface
Replies
18
Views
1K
with this tension problem -- Mass on an accelerating cable
Replies
3
Views
2K
What is the tension in the rope that connects the tugboat
Replies
15
Views
6K
Understanding Tension in a Physics Scenario
Replies
9
Views
2K
Find tension of a rope and kinetic force
Replies
13
Views
2K
Tension on a Massive Rope: How to Calculate Tension at Different Points
Replies
11
Views
3K
Tension force of block and rope
Replies
25
Views
5K
Tension in Ropes: Solving Forces on Trunk
Replies
7
Views
5K
Solve Tension in Rope: 110 Kg Anvil & 9.81m/s^2 Force
Replies
13
Views
2K

Hot Threads

Recent Insights

Back
Top