How much water needed to power the world through oxidization of hydrogen

AI Thread Summary
The discussion centers on calculating the decrease in ocean levels if the world's transportation system were powered by hydrogen oxidization instead of liquid hydrocarbons. The annual energy requirement for this transition is approximately 10^17 kJ, necessitating the electrolysis of seawater to produce 4.17x10^15 moles of hydrogen. Participants suggest using seawater's surface area and the Earth's spherical shape to determine the volume of water involved. The correct approach involves calculating the volume of seawater using molar mass and density rather than the ideal gas law. This analysis highlights the significant impact on ocean levels from such a shift in energy sources.
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Homework Statement


The annual world use of liquid hydrocarbon fuels for transportation purposes currently generates about 10^17 kJ. If we could instead run our transportation system by oxidizing hydrogen gas to gaseous water, we would likely have to obtain the hydrogen by electrolyzing water. Suppose we made and stored enough hydrogen for one year by electrolyzing seawater. By how much would the level of the oceans decrease (in m)?
ΔH=-245.12KJ/mol

Homework Equations


pv=nrt
stoichiometry
electrolyzing water: 2H2O --> 2H2 + O2

The Attempt at a Solution



I have gotten to the point where i have calculated I need 4.17x1015 mol of seawater. I am unsure of how to now calculate the decrease in ocean water.
 
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You might want to search for seawater surface area, that is 71% of the surface area of earth. Consider the Earth spherical with some radius. Convert moles into volume of water and viola, you get your answer.
 
turns out i needed to calculate the volume of seawater by using the molar mass and the density rather than through pv=nrt
 
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