How much work is done on the ball during the acceleration?

AI Thread Summary
The discussion focuses on calculating the work done on a 0.50 kg ball accelerated by an 8.0 N force over a distance of 3.0 m. Initially, the kinetic energy is incorrectly calculated as zero since the ball starts from rest. The work-energy theorem is highlighted as the correct approach to determine the work done, which equals the change in kinetic energy. Since the ball is being accelerated, its velocity will increase, and thus the work done must be calculated to find the final kinetic energy. The conversation emphasizes the importance of correctly applying the work-energy theorem in this scenario.
kelly242
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Homework Statement



A 0.50 kg ball accelerated from rest by a 8.0 N force for 3.0 m

Homework Equations



W=E
Ek= 1/2mv2
Ep=mgh

The Attempt at a Solution


Given: mass= 0.50 Kg, V=0m/s, F=8.0 N, d=3.0 m

Ek=1/2mv2
=1/2(0.50 kg)(0 m/s)2
=o J
That's wrong
 
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How can v be 0 if the ball is being accelerated for a finite period of time? Use the work-energy theorem to calculate the amount of work done on the ball. Since nothing else contributes to the ball's energy, this work must be its kinetic energy.
 
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