How much work is required to lift a 10m chain with 80kg from one end to 6ft?

imranq · Oct 10, 2008

Homework Statement

You have a chain of length 10m with 80kg, how much work does it take to lift this chain from one end to 6ft?

\delta = \frac{10}{80} = .125

W = \int{F(x)}\,dx = \int^{6}_{0}{\delta lg}\,dl = \frac{\delta l^2g}{2}

I don't think that is right though

Redbelly98 · Oct 10, 2008

So far so good, you just need to evaluate the integrated expression at the integral's limits.

Is it 6 ft or 6 m?

imranq · Oct 10, 2008

Oh whoops! Everything that denotes length is in feet

Redbelly98 · Oct 10, 2008

Okay. I'm wondering about the "kg" too then.

imranq · Oct 10, 2008

I don't really remember the problem so well. But the inherent integral should be the same, no? Unless you refer to lbs as weight or something.

Redbelly98 · Oct 10, 2008

Yes, the inherent integral is the same. Using lbs can get a little confusing since lbs are a force unit, not mass.