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How much work was done by a force to accelerate a block

  1. Nov 23, 2007 #1
    Is this right?

    A block of mass 1 kg is acellerated from an initial speed of 2 m/s to a final speed of 6 m/s as it is dragged a distance of 10 m over a level floor. If the coefficient of kinetic friction between the block and the floor is 0.2, how much work must the be done by the applied force?

    Fk = (.2)(9.8) = 1.96N

    WFk = (1.96)(10)(-1) = -19.6J

    W = (1/2)(1)(6^2) - (1/2)(1)(2^2) = 16J

    Wtot = 19.6 + 16 = 35.6J
  2. jcsd
  3. Nov 23, 2007 #2
  4. Nov 23, 2007 #3
    Thank you.
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