How much work was done by a force to accelerate a block

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  • #1
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Is this right?

A block of mass 1 kg is acellerated from an initial speed of 2 m/s to a final speed of 6 m/s as it is dragged a distance of 10 m over a level floor. If the coefficient of kinetic friction between the block and the floor is 0.2, how much work must the be done by the applied force?


Fk = (.2)(9.8) = 1.96N

WFk = (1.96)(10)(-1) = -19.6J

W = (1/2)(1)(6^2) - (1/2)(1)(2^2) = 16J

Wtot = 19.6 + 16 = 35.6J
 

Answers and Replies

  • #2
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Good.:smile:
 
  • #3
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Thank you.
 

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