How Strong is the Attraction Between Two Humans After Electron Transfer?

  • Thread starter Thread starter chukie
  • Start date Start date
  • Tags Tags
    Attraction Human
Click For Summary
SUMMARY

The discussion focuses on calculating the gravitational attraction between two humans after transferring electrons. The participants utilize Coulomb's law, specifically the formula F=kQ1Q2/r^2, to determine the force of attraction. The correct approach involves calculating the net charge after transferring 5 x 10^21 electrons, which alters the initial charge balance of each individual. The final attraction value is derived from the adjusted charges based on the electron transfer.

PREREQUISITES
  • Understanding of Coulomb's law and its application in electrostatics.
  • Knowledge of basic physics concepts such as charge, mass, and distance.
  • Familiarity with scientific notation and calculations involving large numbers.
  • Basic understanding of human tissue composition and electron distribution.
NEXT STEPS
  • Research the implications of charge transfer in electrostatics.
  • Explore advanced applications of Coulomb's law in real-world scenarios.
  • Learn about the relationship between mass, distance, and gravitational force.
  • Investigate the role of protons in balancing electron charge in human tissue.
USEFUL FOR

Physicists, students studying electrostatics, and anyone interested in the fundamental forces between charged particles.

chukie
Messages
79
Reaction score
0
Human tissue contains about 3*10^27 electrons per kg of material. Suppose two humans are located 1370 km apart and each has a mass of 60 kg. We now transfer 5*10^21 electrons from one person to the other. What will be the magnitude of the resulting attraction, rounded to the nearest Newton?

I used the equation F=kQ1Q2/r^2

except I am not sure if I used the right charges.
for Q1, i found it by ((3*10^27)(6)-(5*10^21))(1.6*10^-19)
and Q2: ((3*10^27)(6)+(5*10^21))(1.6*10^-19)
 
Physics news on Phys.org
chukie said:
Human tissue contains about 3*10^27 electrons per kg of material. Suppose two humans are located 1370 km apart and each has a mass of 60 kg. We now transfer 5*10^21 electrons from one person to the other. What will be the magnitude of the resulting attraction, rounded to the nearest Newton?

I used the equation F=kQ1Q2/r^2

except I am not sure if I used the right charges.
for Q1, i found it by ((3*10^27)(6)-(5*10^21))(1.6*10^-19)
and Q2: ((3*10^27)(6)+(5*10^21))(1.6*10^-19)
Why are you using 3 x 10^27? Those electrons are balanced by an equal number of protons so there is 0 net charge. You want to find the net charge after the transfer of 5 x 10^21 electrons.

AM
 
oh okay, thanks! the answer i got now is more reasonable =)
 

Similar threads

Replies
1
Views
1K
Replies
3
Views
2K
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
9K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 2 ·
Replies
2
Views
2K