How the charges are transferred?

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When an electrified plastic rod touches a pith ball, electrons transfer from the rod to the ball, charging it due to the repulsion of like charges. This process occurs because electrons move to the uncharged object, which has a lower potential energy. In a related example, a conducting ping pong ball acquires charge from a high-voltage plate when it touches it, as electric field lines terminate on the ball, causing charge migration. Upon contact, the ball and plate equalize in potential, allowing charge transfer to occur. The interaction illustrates fundamental principles of electric fields and charge distribution.
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"When we touch a pith ball with an electrified plastic rod, some of the negative charges on the rod are transferred to the pith ball and it also gets charged."
I want to know how does this happen ?
 
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The simple answer is that the electrons move from the rod to the ball.
 
why does that happen or how does that happen ?
 
A very simple explanation - like charges repel. Therefore electrons tend to get away from each other to the uncharged thing.
 
Here is a video of a conducting ping pong ball transferring charge between two conducting plates with high voltage (~100,000 volts) on them.



Once the conducting ping pong ball touches a plate, the ball and the plate are at the same potential, and the electric field lines from the other plate terminate on the conducting ping pong ball. Because the field lines terminate on the ball, the ball has charge on it (Gauss's Law). Because this charge is the same sign as the charge on the plate it is touching, it gets repelled by that plate and attracted to the other. When the ball hits the other plate, it deposits its charge, and gets charged by the other plate.

So the charge transfer is due to electric field lines transferring from the plate to the ball when the ball makes contact with the plate. Charge migrates to wherever the electric field lines terminate on the ball.

Look at another way. When an uncharged conducting ball is in an electric field, it has a dipole charge on it, + charge on one end, and - charge on the other. When the ball approaches a plate with + charge on it, the - end of the ball is closest to the plate. When it touches the plate, both the ball and the plate are at the same potential, so the - charge on the closest end of the ball transfers to the plate, leaving only the + charge on the other end.

I hope this helps.

Bob S
 
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