How to Calculate Beta Angle for Pulley B in a Frictional Belt and Pulley System?

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SUMMARY

The calculation of the beta angle for Pulley B in a frictional belt and pulley system is determined to be 120 degrees based on the reference angle of 60 degrees from the top of the pulley. The relationship between the arcs of the two pulleys is established, where the sum of the contact angles from both pulleys equals 360 degrees. The calculation involves subtracting the reference angle from 180 degrees, confirming that the angle reference can be translated between pulleys due to their parallel alignment.

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Homework Statement


I've attached a picture of the problem. I couldn't get beta=120 degrees, for pulley B. How do you get that. Could the question be mistakenly missing this info in the question?
 

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I was thinking about it and drawing circles and lines. Can you tell me if this is a general rule (please look at attachment where I draw circles): when lines are drawn (simulating a rubber band around 2 pulleys), adding blue arcs from both circles will always equal 360 degrees? The blue arc from one circle, and the yellow arc from the other circle are equal in terms of the contact angle, yes?
 

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They get beta = 120 from the given angle of 60 degrees.

180 - 60 = 120 degrees

The 60 degrees is referancing from the top of the pulley. To change the referance point to the bottom of the second pulley they performed the above calculation.

Also, since their referance point is perpendicular to the belt on both pullies they are parallel to each other so the angle referances can then be translated from the larger pulley to the smaller pulley.
 
Last edited:
cool, thx.
 

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