How to Calculate Contact Force Between Boxes in Physics?

AI Thread Summary
To calculate the contact forces between the boxes, first determine the acceleration by dividing the net force of 7.50 N by the total mass of the three boxes, resulting in an acceleration of 0.735 m/s². For the contact force between boxes 2 and 3, multiply this acceleration by the mass of box 3 (5.80 kg), yielding the correct force. However, for the contact force between boxes 1 and 2, the calculation must account for both boxes 2 and 3 being pushed, which requires using the combined mass of those two boxes (m2 + m3) instead of just m2. Understanding that the contact force arises from the boxes being pushed is crucial for accurate calculations.
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Homework Statement



As shown in Figure 5-19, a force of magnitude 7.50 N pushes three boxes with masses m1 = 1.30 kg, m2 = 3.10 kg, and m3 = 5.80 kg.

Figure 5-19
the figure depicts 3 boxes, in order m1, m2, m3 with a force pushing directly on m1 to the right on a flat level surface.

(a) Find the contact force between boxes 1 and 2.
N
(b) Find the contact force between between boxes 2 and 3.
N

Homework Equations



I know you solve for acceleration by taking the fnet of 7.5 N and dividing it by the total mass to get .735 N.

i then was able to get part b by multiplying a, or .735, by the m3, or 5.8 which was the correct answer. however, when i did the same thing for part one, by multiplying a by m2 to get the contact foirce, i was incorrect. please help and explain
 
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papi said:

Homework Statement



As shown in Figure 5-19, a force of magnitude 7.50 N pushes three boxes with masses m1 = 1.30 kg, m2 = 3.10 kg, and m3 = 5.80 kg.

Figure 5-19
the figure depicts 3 boxes, in order m1, m2, m3 with a force pushing directly on m1 to the right on a flat level surface.

(a) Find the contact force between boxes 1 and 2.
N
(b) Find the contact force between between boxes 2 and 3.
N

Homework Equations



I know you solve for acceleration by taking the fnet of 7.5 N and dividing it by the total mass to get .735 N.

i then was able to get part b by multiplying a, or .735, by the m3, or 5.8 which was the correct answer. however, when i did the same thing for part one, by multiplying a by m2 to get the contact foirce, i was incorrect. please help and explain

The contact force between the blocks will come from the blocks that the force is not yet acting through, that is the blocks that are being pushed.

That means your acceleration applied to the masses it is still pushing ahead of the contact point is the source of your contact force.

In part b) the only mass it is pushing is m3. But in part a) you are pushing both m2 and m3.
 
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