How to Calculate Entropy of an Ideal Gas During Expansion?

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Discussion Overview

The discussion revolves around calculating the entropy change of an ideal gas during an expansion process. Participants explore the relevant equations, the role of heat capacity, and the implications of pressure in the calculations. The context includes theoretical and mathematical reasoning related to thermodynamics.

Discussion Character

  • Technical explanation, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant asks how to calculate the entropy change for an ideal gas given specific initial and final conditions, including temperature, pressure, and volume.
  • Another participant requests clarification on the equations related to entropy and their connection to heat capacity, while noting the absence of units in the initial post.
  • A formula for entropy change is proposed: ΔS = nRln(Vf/Vi) + nCv,mln(Tf/Ti), with a question about the mole unit and the value of R.
  • Some participants express uncertainty about the necessity of incorporating pressures into the calculations and seek to understand the reasoning behind this.
  • One participant suggests that to determine the entropy change, a reversible path must be considered, and that the equation provided accounts for the pressure implicitly.

Areas of Agreement / Disagreement

Participants express differing views on the role of pressure in the entropy calculation, with some unsure if it needs to be explicitly included. The discussion remains unresolved regarding the necessity of pressure in the calculations.

Contextual Notes

There are unresolved questions about the assumptions underlying the use of the entropy equation and the dependence on the ideal gas behavior, as well as the implications of the chosen path for calculating entropy change.

ChristineMarie
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How do you calculate the entropy of an ideal gas with n = 1, Cv,m = 1.5R, Ti = 300K, P=3bar and expands against Pext = 1bar until final volume is twice initial volume at Tf = 200K?
 
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ChristineMarie said:
How do you calculate the entropy of an ideal gas with n = 1, Cv,m = 1.5R, Ti = 300K, P=3bar and expands against Pext = 1bar until final volume is twice initial volume at Tf = 200K?
What equations do you know that relate to entropy? How does this relate to the heat capacity? Also, you've left most of your units off!
 
ΔS = nRln(Vf/Vi) + nCv,mln(Tf/Ti).
Only the mole unit, n = 1mol?
R is a constant = 8.3145J/mol.K = 0.083145L.bar/mol.K
 
I'm just not sure how to incorporate the pressures, if I even need to. But if I don't need to use the pressures I would like to understand why.
 
ChristineMarie said:
I'm just not sure how to incorporate the pressures, if I even need to. But if I don't need to use the pressures I would like to understand why.
To get the entropy change from the initial equilibrium state to the final equilibrium state of a system, you need to dream up a reversible path between these two states, and then evaluate the integral of dq/T for that path. In the case of an ideal gas, you also need to take into account the p-v-T relationship for the gas. The equation you wrote down takes all this into consideration, and has done all the work for you. So all you need to do is to substitute the volume ratio and temperature ratio in. The pressure is already implicitly taken into consideration by the equation.

Chet
 
Thank you!
 

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