chetanladha said:
Thank you for your response.
Yes the tank is insulated,and sitting on ground.
Now the upper surface of plate is in contact with the fluid (hot water). How can i find the heat flux?
There are some nice "freeware" packages that will compute this. PM me if you are interested.
If you want to calculate it yourself, do this:
q = U A (T-water - T-outisde)
where,
q = heat loss
U = heat transfer coefficient
A = surface area
T-water = water temperature inside tank
T-outside = outside air temperature.
The heat transfer coefficient is given by:
U = 1 / [ 1/hi + twall/kwall + tins/kins + 1/ho ]
where,
hi = natural convection heat transfer coefficient on inside of tank
twall = tank wall thickness
kwall = tank thermal conductivity
tins = insultation thickness
kins = insulation thermal conductivity
ho = natural convection heat transfer coefficient on outside of tank
Let me know if you need any help figure these values out.