How to calculate initial velocity and launch angle? (Projectiles)

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To calculate the initial velocity and launch angle of a bean bag launched at a corn hole board, the problem provides specific measurements: the bag is released from a height of 0.61m, the board is 5.18m away, and it takes 0.900 seconds to reach the back of the board, which is 0.31m high. The vertical distance can be determined using the heights and flight time, allowing for the calculation of the vertical component of the velocity. The horizontal distance and time can then be used to find the horizontal component of the velocity. Combining these components will yield the initial velocity and launch angle. This approach adheres to the principles of projectile motion.
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Homework Statement


A bean bag launcher is used to shoot a bean bag at a corn hole board. The bag is released at a height of .61m above the ground. The front of the board is 5.18m from the location where the launcher releases the bean bag. The back of the board stands .31 m off the ground; the board has a constant slope.

It takes .900 seconds for a bean bag to reach the very back of the board when launched at some initial angle. Given this information, find the original velocity of the bean bag as it is launched, and the angle of launch.

Homework Equations


The Attempt at a Solution

 
Last edited by a moderator:
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Welcome to PF, puppy143158

You have shown know attempt at a solution, which is against the PF rules. You have been warned.

Here is a hint:

- you know the starting and ending heights. Plugging these, along with the flight time, into the equation for vertical distance vs. time should allow you to solve for the vertical component of the velocity.
 

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