How to Calculate Moles of Gas in a Heated Cubical Vessel Over Time?

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    Thermodynamics
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Homework Help Overview

The problem involves a thermodynamics scenario where a cubical vessel containing air is heated, and the goal is to determine the amount of gas in moles over time, given specific conditions such as thermal resistance and temperature changes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply the first law of thermodynamics and the ideal gas equation, questioning how to proceed with integration given the varying rates of temperature and gas amount.

Discussion Status

Participants are exploring the complexity of the problem, with some questioning the level of difficulty and others suggesting alternative forums for further assistance. There is no explicit consensus on the approach to take.

Contextual Notes

Participants note the problem is suitable for senior secondary level, indicating a specific educational context. The original poster expresses uncertainty about the integration process and the implications of constant pressure assumptions.

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«Challenging» Thermodynamics Problem

Homework Statement



Consider a cubical vessel of edge a, having a small hole in one of its walls. The total thermal resistance of the wall is [itex]\varphi[/itex] [itex]\mbox{At time} \ t=0[/itex], it contains air at atmospheric pressure [itex]p_a[/itex] and temperature [itex]\theta_0[/itex]The temperature of the surrounding is [itex]\theta_a ( > \theta_0 )[/itex] Find the amount of gas in moles in the vessel at time t. Take [itex]C_v = \frac{5R}{2}[/itex]

Homework Equations



[tex]dQ=dW+dU[/tex]
[tex]dQ= \frac{i_{th}}{\varphi}[/tex]
[tex] PV=nR \theta \mbox{ideal gas eqn}[/tex]

The Attempt at a Solution



I assumed pressure to be constant throughout the problem.
[tex]P=P_a[/tex]
Initially,
[tex]i_{th} = \frac{\theta_a - \theta_0}{\varphi}[/tex]
Now since volume and pressure both are constant,
PV=const.
or,
[itex]nRd\theta + R\theta dN = 0[/itex]

[itex]\frac{d\theta}{\theta} = -\frac{dn}{n}[/itex]

Now i try to apply first law, which gives,
[tex]\frac{\theta_a - \theta}{\varphi} dt = nC_vd\theta + \theta C_v n[/tex] where [itex]\theta\ is\ temperature \ at\ time \ t[/itex]
But since these rates are also varying, i have no idea how to continue. Specially if someone could throw light on the integration part.
Thanks for any assistance.
 
Last edited:
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what level is this question?
 
eaboujaoudeh said:
what level is this question?
Senior secondary
 
Any1 got an idea?
 
Long time...if any1 knows a tactic for this do tell :cry:
 
Mabye you should try posting this in the Advanced Physics forum instead?
 

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