How to Calculate Partial Pressure of NOCl in a Chemical Reaction?

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SUMMARY

The calculation of the partial pressure of NOCl in the reaction 2NO (g) + Cl2 (g) ⇌ 2NOCl (g) can be accurately performed using the equilibrium constant Kp, which is given as 6.5×104. By applying the formula Kp = (PNOCl)2 / ((PNO)2 * (PCl2)), and substituting the known values of PNO = 0.35 atm and PCl2 = 0.10 atm, the correct calculation for PNOCl is PNOCl = √((6.5×104) * (0.35)2 * (0.10)). This method is confirmed as valid by participants in the discussion.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with the equilibrium constant Kp
  • Knowledge of partial pressures in gas reactions
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation of the equilibrium constant Kp for various reactions
  • Learn how to calculate equilibrium concentrations from partial pressures
  • Explore the impact of temperature on Kp values
  • Investigate Le Chatelier's principle and its application in equilibrium shifts
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Chemistry students, educators, and professionals involved in chemical engineering or reaction kinetics will benefit from this discussion on calculating partial pressures in equilibrium reactions.

aaronfue
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Homework Statement



I am given the following equation:

2NO (g) + Cl2 (g) \rightleftharpoons 2NOCl (g)

Kp = 6.5×104
PNO = 0.35 atm
PCl2 = 0.10 atm

I need to calculate PNOCl.

Homework Equations



Kp = \frac{(P_{NOCl})^2}{(P_{NO})^2*(P_{Cl_2})}

The Attempt at a Solution



I was given Kp = 6.5×104

After plugging in my partial pressures for NO and Cl2 I got:

PNOCl = \sqrt{(6.5×10^4)*(0.35)^2*(0.10)}

Is this the correct way to calculate this?

Thanks!
 
Last edited:
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That looks good to me!
 

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