How to Calculate Second Order Correlation from Master Equation?

asei
Messages
3
Reaction score
0
Hi,
I have a problem in calculating the second order correlation (coherence) from the master equation for the operators \sigma and a a[+][/SUP] , because I don't know if
<aa^{+}a^{+}a> can be factorized to<a><n><a>.
I want to do this calculation directly from the density matrix solution.
thanks
 
Physics news on Phys.org
This problem is not immediately clear to me. Do you want to calculate the second-order coherence for some light field?

If that is the case, I assume the operators are bosonic, but what exactly does \sigma denote?
And how exactly do you get the \langle \hat{a} \hat{a}^\dagger \hat{a}^\dagger \hat{a} \rangle term? Usually you consider normal-ordering of the operators to account for the effect of the measurement on the light field and get terms like \langle \hat{a}^\dagger \hat{a}^\dagger \hat{a} \hat{a} \rangle.
 
yes you right about the normal ordering, the sigma are the atomic transition operators.
the problem is that when I calculate the mean values of these operators in time, how can I know the second order coherence. can I factorize the expression <A+A+AA> (the plus is dagger) to(<n><n(t)>)? if you know on some reference I will really appreciate it too.
 
Unfortunately, the \langle \hat{a}^\dagger \hat{a}^\dagger \hat{a} \hat{a} \rangle- term does not factorize to \langle \hat{n} \hat{n} \rangle.
Starting with the equal time correlation, you have \hat{a}^\dagger \hat{a} =\hat{a}\hat{a}^\dagger -1, so that the above term factorizes to \langle \hat{n} (\hat{n}-1) \rangle.

This makes sense as the detection of a photon changes the light field by destroying that photon. However, if you are interested in the time dependence of the correlation function, the term \hat{a}^\dagger (t+\tau) \hat{a}(t) can be anything from \hat{a} (t) \hat{a}^\dagger(t+\tau) -1 to \hat{a} (t) \hat{a}^\dagger(t+\tau) depending on the magnitude of \tau compared to the coherence time of the light.

Finding a solution for this problem is rather demanding and depends on the kind of light field you are interested in. I suppose you are interested in lasers. "Classical" atom lasers are for example discussed within a birth-death model in "Photon statistics of a cavity-QED laser: A comment on the laser–phase-transition analogy" by P.R. Rice and H.J. Carmichael, Phys. Rev. A 50, 4318–4329 (1994). Semiconductor lasers are treated using the cluster expansion method in "Semiconductor model for quantum-dot-based microcavity lasers" by C. Gies et al., Phys. Rev. A 75, 013803 (2007).

If you could tell me what kind of system or light field you have in mind, I might be able to come up with more suitable references for your case.
 
Hi
thanks for the help, actually I read the papers as you suggested and I track for more and I find the thing that I want. apparently, in order to calculate the the \left\langle[/a^{+}/a^{+}aa]\right\rangle we have to use the Heisenberg equation for it which depend on the other operators, where in some place I can use factorization in order to get a solution. let&#039;s say I have to generated quantum fields a_{1},a_{2} so in order to find their cross correlation I have to calculate the \left\langle a^{+}_{1}(t)a^{+}_{2}(t+\tau)a_{2}(t+tau)a_{1}(t)\right\rangle in this case what is the difference between t and t+\tau. and maybe because of that we can factorize earlier in the derivations.<br /> thanks for your help
 
Last edited:
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top