How to Calculate the Divergence of a Tensor in MHD?

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SUMMARY

The discussion focuses on calculating the divergence of a symmetric rank 2 tensor (M) in the context of Magnetohydrodynamics (MHD). The integral presented involves the vector (r) and the tensor (M), specifically \(\int_{\partial V} (\textbf{r} d \textbf{S} \cdot \textbf{M}+d\textbf{S} \cdot \textbf{Mr})\). Participants emphasize using the divergence theorem to manipulate the integral into the form \(\int_V {\{\nabla \cdot \textbf{M})\textbf{r}+\textbf{r}(\nabla \cdot \textbf{M})+2\textbf{M}\}dV}\), demonstrating the relationship between volume and surface integrals in tensor calculus.

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Hi guys, trying to solve a problem in MHD, i realized i need to be able to take the divergence of this following integral, but I don't know how to do it.
M is a symmetric rank 2 tensor, r is a vector.

The integral is as follows
\int_{\partial V} (\textbf{r} d \textbf{S} \cdot \textbf{M}+d\textbf{S} \cdot \textbf{Mr})
I need to somehow manipulate this to get \int_V {\{\nabla \cdot \textbf{M})\textbf{r}+\textbf{r}(\nabla \cdot \textbf{M})+2\textbf{M}\}dV}

Thanks
 
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The divergence theorem states that the divergence of a tensor or vector field over a volume V is equivalent to a surface integral of the inner product of the tensor or vector field with the surface basis vectors. So split the integral into the sum of two integrals and use the divergence theorem to prove the equality.
 

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