How to Calculate the Force for a Spring-Powered Putting Machine?

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The discussion centers on calculating the force required for a spring-powered putting machine designed for a golf ball to roll into a hole. The participant seeks to understand the force exerted by the spring and the necessary force to achieve the desired outcome. They initially focused on calculating the coefficient of friction, but confusion arose regarding the relevance of this calculation to their project. Key considerations include the energy involved in the ball's motion, including kinetic energy, potential energy, and rotational energy. The participant is looking for clearer guidance on the physics principles applicable to their project.
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Homework Statement



I am currently enrolled in a Engineering Drafting class. We are working on a group project where we are making a putting machine. We decided on a spring powered device. The ramp's measurements look like this where the goal is to get it into the hole at the end of the ramp.
http://i.imgur.com/o4q0D9X.jpg Its a golf ball rolling on astroturf. Heres the information he gave me when I told him I don't understand fully. http://i.imgur.com/dDhOKrO.jpg
And this is the information when he first explained it. http://i.imgur.com/A9zEuJu.jpg

From my understanding. The Professor wants the amount of force required to hit the ball into the hole. And also how much force the spring is hitting the ball with. I've only dipped my toes into the great ocean of physics and I'm still in pre-calc. This all seems very complicated to me and I have a feeling it's not that hard. Thanks in advance for your help.

Sorry for not embedding the pictures. When I did they were too big.

Homework Equations



This is for calculating the coefficient of friction.

MgH - M /distance = 0
Mg = Mass of golfball = .099lb
H = Height = .038ft
M = coefficient of friction
Distance = 1.65ft (average of 6 tries)
18.4375, 19, 19.3125, 20, 20.0625, 20.4375, 21.3125

The Attempt at a Solution



(.099 * .038) - (M/1.65) = 0
.003762 - M/1.65 = 0
-M/1.65 = -.003762
M/1.65 = .003762
M = .00621
 
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dmarionk said:

Homework Statement



I am currently enrolled in a Engineering Drafting class. We are working on a group project where we are making a putting machine. We decided on a spring powered device. The ramp's measurements look like this where the goal is to get it into the hole at the end of the ramp.
http://i.imgur.com/o4q0D9X.jpg Its a golf ball rolling on astroturf. Heres the information he gave me when I told him I don't understand fully. http://i.imgur.com/dDhOKrO.jpg
And this is the information when he first explained it. http://i.imgur.com/A9zEuJu.jpg

From my understanding. The Professor wants the amount of force required to hit the ball into the hole. And also how much force the spring is hitting the ball with. I've only dipped my toes into the great ocean of physics and I'm still in pre-calc. This all seems very complicated to me and I have a feeling it's not that hard. Thanks in advance for your help.

Sorry for not embedding the pictures. When I did they were too big.

Homework Equations



This is for calculating the coefficient of friction.

MgH - M /distance = 0
Mg = Mass of golfball = .099lb
H = Height = .038ft
M = coefficient of friction
Distance = 1.65ft (average of 6 tries)
18.4375, 19, 19.3125, 20, 20.0625, 20.4375, 21.3125

The Attempt at a Solution



(.099 * .038) - (M/1.65) = 0
.003762 - M/1.65 = 0
-M/1.65 = -.003762
M/1.65 = .003762
M = .00621

Welcome to the PF.

So the golf ball needs to roll to the right up the ramp to get into the hole? And you need to calculate how much force to store in a spring plunger to make that happen? Then why are you calculating a mass M? Sorry that I'm not tracking what you are doing.

You should also include the energy that is invested in the rolling of the ball (that involves the moment of inertia of the ball). The energy of the ball includes the KE of the linear velocity, the PE of the height of the ball above some reference height, and the energy in the rotation of the ball. Does that help?EDIT -- Sorry, I was confused by your multiple uses of M -- why are you calculating the coefficient of friction? You want to calculate the force or impulse or energy stored in the spring pluger, right?
 
I was following the equations that the professor wrote on the board. http://i.imgur.com/A9zEuJu.jpg shows the formula on the bottom. Friction energy was coefficient of friction from my understanding. I think I was using the wrong symbol for coefficient of friction. I thought the greek M was for coefficient of friction. The ball with be level with the astroturf pushed out of a tube by a spring. He wants some basic physics in the report. All the formulas he wrote down do not look like basic physics to me, Its something I haven't really taken yet. If you guys have any recommendations on a better example of they physics behind this project I will take all recommendations. Thank you.
 
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