How to Calculate the Shortest Distance Between Atoms in a BCC Structure?

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To calculate the shortest distance between neighboring atoms in a body-centered cubic (BCC) structure with a cell edge length of 0.5025 nm, one can use geometric relationships inherent in the crystal structure. The BCC arrangement means that the atoms are positioned at the corners and one atom at the center of the cube. The shortest distance between atoms can be derived from the geometry of the cube, specifically by visualizing the triangle formed by the atoms. Using the known edge length, the bond lengths can be calculated through ratios of the triangle sides. This approach avoids the need for Bragg's law, which is not applicable without additional parameters.
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Homework Statement



Barium crystallizes in a body centered cubic structure in which the cell edge length is 0.5025 nm. Calculate the shortest distance between neighboring atoms in the crystal.

Homework Equations



Avagodro's number

The Attempt at a Solution



0.5025 x 10^-7 cm ( 1/2atoms) (6.022 x 10^23 atoms)

That's as much as I know so far, I can't use bragg's law because I don't have the angle nor the order nor the wavelength to figure it out. How should I solve this?
 
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Hi vipertongn! :smile:

I don't know what body centered cubic structure or cell edge length is,

but this looks like a simple geometry problem to me …

they've given you the geometrical pattern and one length, and you have to calculate another length. :wink:
 
http://cst-www.nrl.navy.mil/lattice/struk.picts/a2.s.png

See if you can visualize the triangle...You know the triangle sides. Now calculate the bond lengths from ratios of the triangles.
 
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