How to Calculate Torque in PSI for a Welding Application?

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To calculate torque in PSI for the welding application, the minimum requirement is 250 ft-lbs. The setup involves a cylindrical part constrained by pins, with a bar inserted and a 0.75" cylinder applying force. An air compressor is set at 50 PSI, and the bar length is approximately 1 ft. A formula is needed to convert the torque specification from ft-lbs to PSI, considering the rotational axis of the part. Understanding the relationship between force, area, and torque will be crucial for this conversion.
Aldumoul
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The customer's print calls out 250 ft-lbs mininum on a weld. There was a gage built some time ago... The weld is used to mend a cylindrical feature after forming/stamping the part. There is a bar inserted into the part (part is constrained with pins into a fixture). And the other end of the part is pushed up with a 0.75" Cylinder. An air compressor is set at 50 PSI (someone previously converted to this). The length of the bar is 1 ft (close enough). The part is obviously on a rotational axis. Any ideas as to how one would set up a formula to convert the 250 ft-lbs to PSI?

PART-------------------
(bar) |---|
|_____|
(Cylinder)
 
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My "illustration" didn't turn out correctly. The cylinder is at the end of the bar.
 

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