How to Calculate Travel Time for a Maglev Train in a Vacuum?

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A maglev train in a vacuum can achieve high speeds limited only by passenger g-force tolerance. The travel time can be calculated using the formula t = √(4s/g), where t is time, s is distance, and g is acceleration. An acceleration of 0.5 m/s² allows for a comfortable journey, enabling the train to cross the USA in approximately 1.5 hours. The train accelerates until halfway and then decelerates, with a top speed of 2.7 km/s. The design includes features like rotating chairs for passenger comfort during deceleration.
yrh
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Say we have a maglev train traveling i a vacuum. The only thing limiting its speed is the g-force tolerance of the passengers.

The train would therefore accelerate at a certain rate until halfway, and then decelerate until it reached its destination.

What would be the traveling time of such a train as a function of the distance?
 
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t=\sqrt{\frac{4s}{g}}
where t is the time, s is the distance and g is the accelleration.
Calculated using the fact that distance traveled is the area underneath a velocity-time graph.
 
Thank you.

What acceleration value g should I use? I'm looking for an acceleration/deceleration that is hardly noticeable for the passengers, making the journey comfortable.
 
With an acceleration of 0.5m/s^2 you can cross the USA in 1.5h in a straight line, which is pretty good...

The chairs could turn 180 degrees when the train is going to decelerate. The top speed would be 2.7km/s.

The usual problem with trains is that they start and stop at all the intermediate stations...
 
yrh said:
Say we have a maglev train traveling i a vacuum. The only thing limiting its speed is the g-force tolerance of the passengers.

The train would therefore accelerate at a certain rate until halfway, and then decelerate until it reached its destination.

What would be the traveling time of such a train as a function of the distance?

At the distance x the train is accelerated until x/2 so the time is expressed as:
x/2=gt²/2
t=√x/g
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...

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