How to Calculate Velocity of a 4-Wheeled Vehicle Using a Pulley System

  • Thread starter Thread starter henry1117
  • Start date Start date
AI Thread Summary
To calculate the velocity of a 4-wheeled vehicle using a pulley system, start by analyzing the forces acting on both the weight and the vehicle through free body diagrams. The weight experiences gravitational force and tension, while the vehicle is influenced by tension and friction. Using Newton's second law, derive equations for both the weight and the vehicle's motion, ensuring to account for the normal force and frictional force. By knowing three variables among tension, mass of the block, mass of the car, and the coefficient of friction, you can solve for acceleration. Once acceleration is determined, apply kinematic equations to find the vehicle's velocity at any given time.
henry1117
Messages
8
Reaction score
0
Ok basically i need help to start off a question as a part of a research type thing.

i need to find out the velocity of a 4 wheeled vehicle if string is wrapped around the rear axel of the vehicle multiple times and the string then extends up above the rear axel onto a pulley where a weight sits.

Basically, as the weight is let go and falls, the vehicle starts moving and i need to know the velocity of the vehicle after the weight has fallen.

so ye, if anyone could start me off on this it would be greatly appreciated
 
Physics news on Phys.org
henry1117 said:
Ok basically i need help to start off a question as a part of a research type thing.

i need to find out the velocity of a 4 wheeled vehicle if string is wrapped around the rear axel of the vehicle multiple times and the string then extends up above the rear axel onto a pulley where a weight sits.

Basically, as the weight is let go and falls, the vehicle starts moving and i need to know the velocity of the vehicle after the weight has fallen.

so ye, if anyone could start me off on this it would be greatly appreciated

As in all Classic Newton problems, let's start off with Free body diagrams, indicating the forces acting on all bodies of interest. It looks like our FBD for our mass A attatched to the pulley is only acted upon by gravity, downwards, in what we'll call the positive y direction, and tension upwards from the pulley, which we'll call T1 (Lets assume no friction in the pulley)
Our FBD for the car shows a positive tension in our x axis, called T2, and a negative friction along the table (or road) working against the direction of motion. There is also the force of gravity working down on the car, and a normal force acting upwards, but since the table is rigid, and the car is not falling through the road, we can show that Fgcar = FN

Now we will use Newton's 2nd law to derive two important equations that will lead to solving for our unknowns.

Looking at the mass on the pulley, the force in the y direction will be the sum of the forces acting on it, which is simply gravity, and that will equal ma

Fblocky = Fg - T1 = Mblockablock

Next let's look at the motion of the car in the x direction:

Fcarx = T2 - Ff = Mcaracar

Now that we have these two equations, its time to look at some constraints.

We've already discussed that Fgcar = FN for a rigid body, so Mcarg = N (our normal force, which we will need to solve for the force of friction)

Since the whole system is moving together, we can assume that ablock = acar = a

To find our frictional force Ff, it is given by \muN, where \mu is the coefficient of friction.

So, with these two equations, as long as you know 3 of the following unknowns: T1, T2, Mblock, Mcar, \mu, you can use your two equations and two unknowns to solve for acceleration a. Once you know that, you can describe the speed of your system (and hence your car) at any given time at any position, given simple kinematic equations that can be looked up.

hope this helps,

cheers
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top