Python How to check a string is odd palindrome in python?

[shivajikobardan]

I am learning to code and 1 thing that surprises me is how do I internalize all the code? I understand the code. I know the algorithm as well. But I want to be able to solve any types of problems(related ones) after learning 1 code. How do I become able to do that? So for that I am first trying with palindrome program.
Here is the palindrome program for even palindrome.

#palindrome checking

str1="abba"
for i in range(len(str1)//2):
    if(str1[i]==str1[len(str1)-i-1]):
        isPalindrome=True
    else:
        isPalindrome=False
print(isPalindrome)

Now I want to write code for odd palindrome. Don't show me code but show me direction or algorithm so that I can write code on my own.
example of odd palindrome is abbcbba. We are using c as the middle point.

 

[shivajikobardan]

#palindrome checking

str1="abcba"
if(str1[len(str1)//2]=="c"):
    for i in range(len(str1)//2):
        if(str1[i]==str1[len(str1)-i-1]):
            isPalindrome=True
        else:
            isPalindrome=False
print(isPalindrome)

 

[Jameson]

If you want more functional code and care less about the fastest implementation then I would reverse the string first and compare letter by letter. This just makes it more intuitive. https://stackoverflow.com/questions/931092/reverse-a-string-in-python

In your loop you check the letter with the mirror position on the opposite side, which looks good, but you overwrite the isPalinidrome indicator and this could lead to issues. All that matters in your code is the last iteration of the loop. I would modify this so that any time this returns False then we stop the loop and return False.