How to convert an inch dimension to arc minutes for precise measurement?

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Discussion Overview

The discussion revolves around converting an inch dimension to arc minutes, specifically in the context of ensuring a 3-foot diameter roll does not move more than 1/8 inch. Participants seek to understand the conversion for comparing it to the backlash in gearing systems.

Discussion Character

  • Technical explanation, Mathematical reasoning, Debate/contested

Main Points Raised

  • One participant asks how to convert an inch dimension to arc minutes, providing the context of a customer requirement for a roll's movement.
  • Another participant notes that 1/8 inch is a fraction of the circumference and relates it to the associated angle in arc minutes.
  • A calculation is presented where one participant computes the angle as 23.87 arc minutes using a radius of 18 inches.
  • Another participant challenges the previous calculation, providing a different method and arriving at the same angle of 23.87 arc minutes after correcting an earlier mistake.
  • A different approach is suggested using the navigational offset rule, leading to an estimate of 25 arc minutes based on a radius of 18 inches.
  • One participant acknowledges the contributions and expresses gratitude for the replies.

Areas of Agreement / Disagreement

There is some disagreement regarding the calculation methods and results, with different participants arriving at similar final values through varying approaches. However, no consensus on a single method is reached.

Contextual Notes

Participants utilize different assumptions and methods for their calculations, leading to variations in results. The discussion does not resolve the differences in approaches or the implications of the navigational rule used.

SevenToFive
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How can l convert an inch dimension to arc minutes? We have a customer who requires a 3 foot diameter roll not move more than an 1/8 inch. I need to convert the 1/8 inch to arc minutes to compare to the backlash in our gearing.

Any help is greatly appreciated.
 
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SevenToFive said:
How can l convert an inch dimension to arc minutes? We have a customer who requires a 3 foot diameter roll not move more than an 1/8 inch. I need to convert the 1/8 inch to arc minutes to compare to the backlash in our gearing.

Any help is greatly appreciated.
1/8" is a fraction of the circumference and arc min is the associated angle.
 
18" is radius and the angle is [1/(8*18)] rad = [{(180*60)/(8*18)}/π] arc min = 75/π = 23.87 arc min
 
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I get a different answer, by a factor of π.
D =36"
Allowed Move = 1/8" = 0.125"
Circumference = π⋅D = 113.1"
Circum/Allowed Move = 113.1/0.125 = 904.8 (the fraction of a revolution req'd to move 1/8")
Allowed Rotation = 360°/904.8 = 0.3979° = 23.87 arc min
 
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Tom.G said:
I get a different answer, by a factor of π.
D =36"
Allowed Move = 1/8" = 0.125"
Circumference = π⋅D = 113.1"
Circum/Allowed Move = 113.1/0.125 = 904.8 (the fraction of a revolution req'd to move 1/8")
Allowed Rotation = 360°/904.8 = 0.3979° = 23.87 arc min
I am sorry I had committed a calculation mistake,now I also get the same answer.
 
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For small angles, a quick estimate can use the navigational offset rule of “1 in 60, per degree”.
So 1/8” on a radius of 18” = 1 in ( 18 * 8 ) = 1 in 144.
Apply the 1 in 60 rule, then multiply degrees by 60, to get ( 60 * 60 / 144 ) = 25 arc min.

The 1 in 60 navigation rule comes from 1 radian ≈ 57.29578 degrees.
Mathematically we have ( 60' * 57.29578° / 144 ) = 23.8732 arc min.
 
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Thanks everyone for the replies. Greatly appreciated.
 
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