How to convert pressure (Bar) to flow rate (L/min)?

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SUMMARY

This discussion focuses on calculating the pressure required to achieve a flow rate of 3 L/min for Argon gas, considering a pipe with an internal radius of 2.3 mm and a pressure range of 0 to 5 bar. Key insights include the importance of pipe length in determining pressure drop, as well as the need to account for gas compressibility when pressure changes significantly. The methodology for solving this problem is outlined in Chapter 7 of "Transport Phenomena" by Bird, Stewart, and Lightfoot, emphasizing the use of absolute pressure in calculations.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with pressure drop calculations
  • Knowledge of gas compressibility factors
  • Access to "Transport Phenomena" by Bird, Stewart, and Lightfoot
NEXT STEPS
  • Learn how to calculate pressure drop in pipes using the Darcy-Weisbach equation
  • Study the effects of gas compressibility on flow rates
  • Explore the relationship between pipe length and pressure drop
  • Review the principles of flow rate measurement for gases
USEFUL FOR

Engineers, physicists, and anyone involved in fluid mechanics or gas flow calculations will benefit from this discussion, particularly those working with gas systems and pressure management.

avishay
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hii,

I'm try to calculate the pressure (in bar) needed for a certain flow rate 3 L/min of Argon gas given the following setup:
- I have a tank of Argon gas and the line pressure can be between 0 bar to 5 bar.
- The gas will flow out to the open air in the end.
- My pipe has an internal radius of 2.3mm.

I will be very happy if someone can also explain to me the process of getting to the answer...

Thanks for the help :)
 
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Hello avishay, ##\qquad## :welcome: ##\qquad## !

Your problem statement isn't complete: for a short pipe the pressure drop is less than for a long pipe.

With the expressions in the link you can calculate ##\Delta p## for your pipe length.
 
I didnt really understod how to calculate this prameter, I'm not really sure why i need this...
any help?
:)
 
avishay said:
I didnt really understod how to calculate this prameter, I'm not really sure why i need this...
Pressure drop is a function of length or rather is given per unit length.
 
avishay said:
calculate this parameter
It's not really a parameter: according to the link it's a result of a bunch of variables.

What have you calculated yourself so far ?
 
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The methodology for solving a problem like this is presented in Chapter 7 of Transport Phenomena by Bird, Stewart, and Lightfoot. But, please note that, in a case like this where the gas pressure change can be as large as a factor of 6, you will need to take into account the compressibility of the gas, and, as such, will probably be working in terms of the square of the absolute pressure (rather than the absolute- or gauge pressure to the 1st power).
 

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