How to Correctly Apply Integration by Parts to ln(x-7)?

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Homework Help Overview

The discussion revolves around the application of integration by parts to the integral of ln(x-7)dx, which is part of a larger problem. Participants are exploring the nuances of integrating logarithmic functions and the implications of arbitrary constants in integration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply u-substitution and integration by parts but expresses uncertainty about the resulting constant in their answer. Some participants discuss the nature of the constant of integration and its implications in the context of differential equations.

Discussion Status

Participants have provided guidance regarding the treatment of the constant of integration, noting that it can be considered arbitrary. There seems to be a productive exchange about the correctness of the integration process and the interpretation of constants.

Contextual Notes

The original poster mentions that the integral is part of a differential equation, which adds significance to the constant of integration in their solution.

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[SOLVED] integration by parts question

Homework Statement


This is part of a larger problem but I'm just not sure if I have the right answer.

edit: this is integral of ln(x-7)dx i just can't seem to figure out how to make it in latex


Homework Equations





The Attempt at a Solution


u-substituion:

u = x - 7

du = dx

Integration by parts to get

\intlnudu = ulnu - \int1du

= ulnu - u

= (x - 7)ln(x - 7) - (y - 7) + C

Now my only problem with this answer is that it gives 7 + C as part of the answer, and I can't recall ever seeing a constant + C as the answer for any integral.

I actually plugged the equation into this integral finder:

http://integrals.wolfram.com/index.jsp

And it told me that it was

(x-7)ln(x-7) - x

I'm guessing the +C is a given.

I would just leave it at +C and go on but its part of a differential equation so the value of C ends up being important...
 
Last edited:
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C is not just a constant in the integration. It's an ARBITRARY constant. There is no difference between C and C+7. Just leave it at C and go on.
 
Alright thanks :)
 
You mean x-7 and a constant plus a constant is a constant. Both you and mathematica have the right answer, but mathematica just absorbed the 7 into the constant. Differentiate it to check. :)
 

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