Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How to deal with the j?

  1. Aug 21, 2008 #1
    given z is complex, sketch the following locus on the Argand diagram:

    {(z-3+j)/(z-j) }= square roots of 5

    { }= modulus .

    hope anyone can guide .
  2. jcsd
  3. Aug 21, 2008 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    First, you use "i" instead of "j" like a normal human being, not an engineer!:rofl:

    "Square" both sides to get
    [tex]\frac{(z-3+ i)(\overline{z}-3-i)}{(z+i)(\overline{z}- i)}= 5[/itex]
    Setting z= x+ iy that is
    [tex](x-2 + i(y+1))(x- 2)- i(y-1)= 5(x+ i(y+1))(x- i(y-1))[/itex]

    Multiply that out and separate real and imaginary terms.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?