How to derive formula for nucleus decay using this equation?

AI Thread Summary
The discussion focuses on deriving the formula N=No*e^kt from the equation Nn=No/2^n, where No represents the initial number of particles and n indicates the number of half-lives. The decay constant k is also mentioned, defined as k=-0.693/t. Participants emphasize that while they can provide guidance, they will not complete the homework for others. The thread highlights the importance of understanding the relationship between half-lives and exponential decay in nuclear physics. Engaging with the material and asking specific questions is encouraged for effective learning.
Gwyndolin
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Homework Statement


The formula being derived is N=No*e^k*t, from the equation Nn=No/2^n where No is the initial number of particles and the lowercase n in the second equation is the number of half lives. The n in Nn just indicates the number of particles after so many half lives. You might also use the formula for the decay constant so feel free to.

Homework Equations


N=No*e^kt
Nn=No/2^n
k=-.693/t

The Attempt at a Solution


I haven't really made any meaningful progress so I leave it to you!
 
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Gwyndolin said:

Homework Statement


The formula being derived is N=No*e^k*t, from the equation Nn=No/2^n where No is the initial number of particles and the lowercase n in the second equation is the number of half lives. The n in Nn just indicates the number of particles after so many half lives. You might also use the formula for the decay constant so feel free to.

Homework Equations


N=No*e^kt
Nn=No/2^n
k=-.693/t

The Attempt at a Solution


I haven't really made any meaningful progress so I leave it to you!
Sorry. PF is not a Homework service. You'll have to do the work, and we'll answer questions and make suggestions if you get stuck.
 

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