lemonlee
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Homework Statement
2x^2+5xy-y^2=1
Homework Equations
d/dx(f(u)x))=df/du * du/dx
The Attempt at a Solution
i got (2y-4x)/5x but I'm almost certain that its wrong...can anyone help me?
How to Derive Using the Chain Rule for 2x^2+5xy-y^2=1?
- Thread starter lemonlee
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2x^2+5xy-y^2=1
d/dx(f(u)x))=df/du * du/dx
i got (2y-4x)/5x but I'm almost certain that its wrong...can anyone help me?
Discussion
Homework Helper
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lemonlee said:
Assuming that you are trying to find [tex]\frac{dy}{dx}[/tex] (you didn't actually tell us what you are trying to calculate!), then it is wrong...However, I can't tell you what you did wrong since you haven't shown me what you did to get your answer...if you do that, I'll be able to help you
