How to Determine Focal Length and Power of Lenses for Farsightedness

AI Thread Summary
To determine the focal length and power of lenses for a farsighted woman who struggles to see objects closer than 60 cm, the relevant equations are 1/p + 1/q = 1/f for focal length and P = 1/f for power. The object distance (p) for the book is 25 cm, while the image distance (q) must be set to 60 cm to ensure clarity for her vision. By substituting these values into the equations, one can calculate the necessary focal length (f) and subsequently the lens power (P). The challenge lies in correctly identifying the object and image distances in relation to the lens and the eye. Ultimately, the calculations will provide the specifications needed for the corrective lenses.
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Homework Statement


A farsighted woman cannot see objects clearly that are closer to her eye than 60.0 cm. Determine the focal length and power of the spectacle lenses that will enable her to read a book at a distance of 25.0 cm.


Homework Equations


The equation I have been using to find the focal length is: 1/p + 1/q = 1/f

For the magnifying power, I believe that equation is 1/f = P


The Attempt at a Solution



I've been getting stuck after setting p to infinity which my instructor said to do, then I'm left with 1/q = 1/f ... I don't see how that helps me narrow down my attempt in solving the problem. I understand that the woman needs a min of 60 cm length for the image to be perfectly seen in her eye but I'm not seeing how to incorporate the other information presented in the problem.
 
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The book is at 25 cm distance from the eye, but the women can see something not closer than 60 cm. If the image of the book is at 60 cm, would she see it? What are the object distance and image distance then? And you can assume that the eye and the lens are at the same place. distance from the eye is the same as the distance from the lens.

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