# How to determine the diameter of a cable

A Cable that has a yield strength of 620 MPa and a safety factor of 3. This cable must be able to support 5 buckets which must be able to carry up 5,429.554 kg each.
Bucket mass is negligible.

Stress = Mass/Area
Area = force/stress

My attempt at a solution:
Total weight 5 buckets must carry = 5,429.554 kg * 5 = 27147.77 kg

Area = 27147.77kg * 9.8ms^2 / 206.667MPa x 10^6
Area = .00128

.00128 = ∏d^2 / 4
.00164 = d^2
.040496m = d
or 40.497mm

I know this is probably all wrong.

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rock.freak667
Homework Helper
That looks correct to me, your method at least, I don't have a calculator right now to check your numbers.

CWatters
Homework Helper
Gold Member
Calculation looks ok as well.

Wouldn't this methodology be a bit wasteful design wise? In addition to utilizing a specified factor of safety the loading is then taken to be occurring in one specific point as a combined whole when in reality the buckets are five distinct and spaced point loads?

CWatters