MHB How to Distribute in an Algebra Problem

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To simplify the expression 2(x^2+y^2)(2x+2yy'), distribute (x^2+y^2) across the terms in parentheses. This results in 4x(x^2+y^2) + 4y(x^2+y^2)y'. The key is recognizing that each term in the parentheses must be multiplied by the factor outside. This process clarifies the transition between the two forms of the equation. Understanding distribution is essential for solving similar algebraic problems.
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Hi working on an algebra/calculus problem

How do I get from

2 (x^2+y^2) (2x+2yy')

to 4x (x^2+y^2) + 4y(x^2+y^2) y'

It is very confusing.

Tim
 
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tmt said:
Hi working on an algebra/calculus problem

How do I get from

2 (x2+y2) (2x+2yy')

to 4x (x2+y2) + 4y(x2+y2) y'

It is very confusing.

Tim

Did you mean, how do you get from $2(x^{2}+y^{2})(2x+2yy')$ to $4x(x^{2}+y^{2})+4y(x^{2}+y^{2})y'$? Because, if so, that's just distributing the $(x^{2}+y^{2})$ times the other stuff in parentheses.
 
Ackbach said:
Did you mean, how do you get from $2(x^{2}+y^{2})(2x+2yy')$ to $4x(x^{2}+y^{2})+4y(x^{2}+y^{2})y'$? Because, if so, that's just distributing the $(x^{2}+y^{2})$ times the other stuff in parentheses.
Yes I did,

Thank you!
 
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