The discussion centers on the algebraic manipulation of the expression 2(x²+y²)(2x+2yy'). The correct transformation to achieve is 4x(x²+y²) + 4y(x²+y²)y'. The key operation involved is the distribution of the term (x²+y²) across the sum (2x + 2yy'). This process clarifies the steps necessary for simplifying the expression correctly.
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tmt said:Hi working on an algebra/calculus problem
How do I get from
2 (x2+y2) (2x+2yy')
to 4x (x2+y2) + 4y(x2+y2) y'
It is very confusing.
Tim
Yes I did,Ackbach said:Did you mean, how do you get from $2(x^{2}+y^{2})(2x+2yy')$ to $4x(x^{2}+y^{2})+4y(x^{2}+y^{2})y'$? Because, if so, that's just distributing the $(x^{2}+y^{2})$ times the other stuff in parentheses.