How to find distance when a ball rolls slope with angle?

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To find the distance a steel ball travels after rolling down a slope and launching horizontally, the initial velocity must be calculated using energy conservation principles. The ball's final velocity can be determined from the height and slope angle, with a calculated speed of 3.74 m/s noted. The discussion highlights the importance of considering both translational and rotational energy for accurate results. Additionally, clarification on the physics class level is suggested to better tailor the solution approach. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement


A) For a steel ball rolling down a 35 degree slope from a height of .5 m above the table, how far will the ball travel in the x direction if it launches horizontally from the table which is 1m high

For the same ball rolling down a 45 degree slope from one meter high, what maximum diameter of loop the loop will the ball go around without falling? Show work?

Homework Equations


a=v^2/r
V=sqtroot(10/7)xgh
g=9.8m/s

The Attempt at a Solution


I got V= 3.74m/s which seems pretty high/fast and then idk what else to do to find the distance. Any help would be great!
 
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physicsstudent101 said:

Homework Statement


A) For a steel ball rolling down a 35 degree slope from a height of .5 m above the table, how far will the ball travel in the x direction if it launches horizontally from the table which is 1m high
I think you need to show more of the details of your work so far. How did you find the final velocity? Do you need to take into account the rotational energy of the steel ball?

Perhaps you could tell us what physics class level this problem is aimed at?
 
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