How to Find Instantaneous Displacement in a Sinusoidal Wave?

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To find the instantaneous displacement in a sinusoidal wave described by the function s(x,t)=(2.00 μm)cos[(15.7 m^(-1))x-(858 s^(-1))t], the correct substitutions must be made for x and t. At x = 0.050 m and t = 3.00 ms, the calculation simplifies to s(0.050, 0.003) = (2.00 μm)cos[1.789 rad]. The cosine of 1.789 rad yields an instantaneous displacement of approximately -0.433 μm. Ensuring the calculator is set to the correct mode (radians) is crucial for accurate results.
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Homework Statement



A sinusoidal sound wave is described by the displacement wave function
Code:
s(x,t)=(2.00 μm)cos⁡[(15.7 m^(-1) )x-(858 s^(-1) )t]
b) Determine the instantaneous displacement from equilibrium of the elements of air at the position x = 0.050 m at t = 3.00 ms

Homework Equations





The Attempt at a Solution


Code:
s (x,t)=(2.00 μm)  cos⁡[(15.7 m^(-1) )(0.050m)-(858 s^(-1) )(.003 s) ]

Why is this this not correct?
 
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Your substitutions are correct.
What is s = ?
 
s = 3ms
the answer is supposed to be -.433 μm
 
When you simplify the terms inside the bracket, you get 1.789 rad. To find the cos of this, either change the mode in your calculator to RAD or convert 1.789 rad to degrees and then solve for s.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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