How to Find Speed and Tension in a Swinging Rock?

Noke2011
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Maximum Tension and Trajectories?

Homework Statement



A rock of mass 3.3kg is tied to a string of length 1.2m. The rock is held at rest (at an angle of 25 degrees) so that the string is initially tight, and then it is released. (A) Find the speed of the rock when it reaches the lowest point of its trajectory. (B) What is the maximum tension in the string?


Homework Equations



T=ma


The Attempt at a Solution



Okay, so the max tension is the amount of tension that can be applied so that the string is taught, therefore T=(3.3)(9.8)=32.34N. However, my question is, if it's held taught, and the string length cannot change, wouldn't the lowest point of the trajectory be the point at which the string is held?
 
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The string length will stay the same and the string will still be taught, but the angle(and therefore the x and y coordinates of the rock) will change after released.
 


But how do I find the speed of the rock at this angle? I'm not sure where to begin, would the angle just be the opposite of 25 degrees?
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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