lreichardt Messages 4 Reaction score 0 Thread starter Mar 31, 2008 #1 How do I take the derivative of f(x)=ln[x/(x-1)]? Thanks!
tiny-tim Science Advisor Homework Helper Messages 25,837 Reaction score 258 Mar 31, 2008 #2 Welcome to PF! Hi lreichardt! Welcome to PF! Just use the chain rule: derivative of ln, times the derivative of x/(x-1).
Welcome to PF! Hi lreichardt! Welcome to PF! Just use the chain rule: derivative of ln, times the derivative of x/(x-1).
lreichardt Messages 4 Reaction score 0 Mar 31, 2008 #3 so, (x/1)(quotient rule of x/(x-1)? = (x/1)(-x/x-1)=-x^2/x-1
tiny-tim Science Advisor Homework Helper Messages 25,837 Reaction score 258 Mar 31, 2008 #4 ooh dear … better go the easy way … simplify it first … ln(x/(x-1)) = ln(x) - ln(x-1) … now differentiate!
ooh dear … better go the easy way … simplify it first … ln(x/(x-1)) = ln(x) - ln(x-1) … now differentiate!
kelten Messages 1 Reaction score 0 Apr 6, 2008 #5 Chain rule = The difference of the derivative of the "Outer" and derivative of the "Inner", put simply.
Chain rule = The difference of the derivative of the "Outer" and derivative of the "Inner", put simply.