How to Find the Derivative of f(x)=ln[x/(x-1)]?

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Homework Help Overview

The discussion revolves around finding the derivative of the function f(x) = ln[x/(x-1)], which falls under the subject area of calculus, specifically focusing on differentiation techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the chain rule and the quotient rule in finding the derivative. There are attempts to simplify the expression before differentiation, with some suggesting using properties of logarithms.

Discussion Status

The discussion includes various approaches to the problem, with participants offering different methods and clarifications. While one participant expresses confidence in having figured it out, there is no explicit consensus on a single method being the best approach.

Contextual Notes

Some participants question the complexity of the derivative process and suggest simplifications, indicating a potential lack of clarity in the original function's setup.

lreichardt
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How do I take the derivative of

f(x)=ln[x/(x-1)]?

Thanks!
 
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Welcome to PF!

Hi lreichardt! Welcome to PF! :smile:

Just use the chain rule: derivative of ln, times the derivative of x/(x-1). :smile:
 
so, (x/1)(quotient rule of x/(x-1)? =

(x/1)(-x/x-1)=-x^2/x-1
 
ooh dear …

better go the easy way … simplify it first …

ln(x/(x-1)) = ln(x) - ln(x-1) … now differentiate! :smile:
 
Chain rule = The difference of the derivative of the "Outer" and derivative of the "Inner", put simply.
 
Thanks all, figured it out.
 

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