How to find the velocity needed to melt a snowball

  • Thread starter Thread starter TextClick
  • Start date Start date
  • Tags Tags
    Velocity
AI Thread Summary
To determine the velocity needed for a snowball to completely melt upon impact, one must calculate the heat required to melt the snow, using the heat of fusion (Hf) and the assumption that 75% of the generated heat is absorbed. The kinetic energy (KE) of the snowball, represented by the equation KE=1/2mv^2, must equal the heat energy required for melting. It's important to express the solution in terms of a variable mass, as the specific mass of the snowball is unknown. Posting detailed workings is essential for clarity and to receive guidance on any confusion. Engaging with the problem and sharing calculations will facilitate better assistance.
TextClick
Messages
7
Reaction score
0
Homework Statement
With what velocity must a snowball at 0 C be thrown so that it completely melts upon striking a stone wall? (Assume 75% of the heat generated is absorbed by the snow.)
Relevant Equations
Q=mCdeltat
Q=mHv
Q=mHf
KE=1/2mv^2
PE=mgh
I attempted a solution, but I was unfortunately confused and did not know how to do the problem. As a result, I did not do any work.
 
Physics news on Phys.org
TextClick said:
Homework Statement:: With what velocity must a snowball at 0 C be thrown so that it completely melts upon striking a stone wall? (Assume 75% of the heat generated is absorbed by the snow.)
Homework Equations:: Q=mCdeltat
Q=mHv
Q=mHf
KE=1/2mv^2
PE=mgh

I attempted a solution, but I was unfortunately confused and did not know how to do the problem. As a result, I did not do any work.
Nevertheless, you need to post an attempt, no matter how confused. That way we may be able to see where you are confused and help you become unconfused.
 
IMG_7456.jpg
 
You arrived at an answer, but it is impossible to tell from those few scribbles how you arrived at the required energy. Please post the details of your working , and not as an image. Per forum rules , images are for textbook extracts and diagrams.
 
Pretty sure you are meant to determine the amount of heat required to melt a unit of snow. That's what the Hf is for. Then you are supposed to find out how fast it must be moving so that 3/4 of it's Ek equals that much.

So you should do the problem with a variable mass, since you don't know what the mass of a snowball is. But the mass should divided out at the end.

It looks like the person who marked this quiz wrote the correct answer for you. They even wrote the equations.

Can you make an attempt?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top