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Homework Help: How to find this answer using logarithmic table?

  1. Sep 25, 2016 #1
    [Mod Note: moved into homework forum, so template not present]

    3/5840=0.00051
    How to find this answer using logarithmic table? Thanks in advance.?
     
  2. jcsd
  3. Sep 25, 2016 #2

    BvU

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    What do you do to find the logarithm of a product ?
    And what for the logarithm of a quotient ?
     
  4. Sep 25, 2016 #3
    What kind of logarithmic table do you have available?
     
  5. Sep 25, 2016 #4
    I want to find quotient of 3 and 5840.
     
  6. Sep 25, 2016 #5
    We know.

    Now answer our questions.
     
  7. Sep 25, 2016 #6
    I am using Logarithmic table (of 11th standard student).
     
  8. Sep 25, 2016 #7
    That doesn't tell us anything. Please describe the table or attach a picture.

    And answer BvU too.
     
  9. Sep 25, 2016 #8

    rcgldr

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    My guess is the table is similar to the one in the CRC series of books. It's a table of 900 logs (base 10) for values 0.100 to 0.999, to 4 decimal places. The CRC books explain how to use the log tables.
     
  10. Sep 25, 2016 #9

    Mark44

    Staff: Mentor

    You need to convert all of the numbers involved into a form similar to scientific notation. For this problem, 3 = .3 * 101, so log(3) = log(.3 * 101) = log(.3) + log(101) = log(.3) + 1

    To calculate the log of a product, use the fact that log(AB) = log(A) + log(B). To calculate the log of a quotient, use the fact that log(A/B) = log(A) - log(B).
     
  11. Sep 25, 2016 #10

    BvU

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    Thanks Mark for answering my question...:wink:... however, it was meant for Dinesh....
     
  12. Sep 26, 2016 #11

    symbolipoint

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    Old textbooks on Intermediate Algebra had good instructions for how to use log tables. Those would be the best way to learn this. Learning to use such tables will require some studying, maybe a couple of weeks if you are new to this; maybe a couple hours or so if you had done it previously. All the while, keep reminding yourself the meaning of LOGARITHM, base, and ANTI-LOG. Not telling you how. I'm just suggesting where to look.
     
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