How to get capacitance from potential FEM

AI Thread Summary
To determine the capacitance of a non-linear capacitor using FEM simulations, the charge (Q) needs to be calculated from the electric field, which relates to the surface charge density via Gauss's law. The potential obtained from the simulation can be used to find the charge density by calculating the Laplacian of the potential. It is important to integrate the charge density over the volume rather than just the surface. Additionally, the presence of water between the plates may lead to polarization effects when a potential difference is applied. Understanding these relationships is crucial for accurately calculating capacitance in this setup.
rinale84
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Hi guys,
I hope this is the correct section otherwise I apologize :).The goal is to find the capacity of a non linear capacitance composed by an upper plate which has a cup shape and the lower plate which is flat.
The problem is the following: by means of a FEM simulation of the Poisson equation I was able to find the potential but once I got it how can I get the capacitance?
 
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C = Q/V

You still need the charge.
If it is not immediately available, you need to calculate it:
- the field at the surface gives the charge density
- summing over the whole surface will provide Q
 
Excuse my silly question I don't remember why the electric filed at the surface gives the surface charge density..thank u very much
 
Not exactly the electric field but the divergence of electric field. Thats the differential form of gauss law http://en.wikipedia.org/wiki/Gauss_law#Differential_form

Since you have the potential, it is the laplacian of the potential that gives the charge density.

PS i don't remember how to calculate the laplacian for numerical data.
 
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I think some function in MATLAB will be helpful... But the integration of the chrage density should be performed on the volume and not on the surface!Am i wrong?
 
I am not sure I am in this situation the plates of the capacitor are made of a polymer and inside the two plates we have water. Above the polymer there is a layer of conductive material on which we apply the potential...Besides how the charge will behave when i apply a potential difference among the plates? The water should polarize am I wrong? Sry if I forgot this fundamental detail before...
 
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