How to graph a function by transforming a graph of a function form?

AI Thread Summary
To graph the function y=(x-3)^2, one must start with the graph of y=x^2 and apply a transformation. The transformation involves shifting the graph of y=x^2 horizontally to the right by 3 units. The reference to y=x^n indicates that n should be chosen as 2 to align with the quadratic function. This process clarifies how to transition from the general form y=x^n to the specific function y=(x-3)^2. Understanding this transformation is key to accurately sketching the graph.
frozenbananas
Messages
8
Reaction score
0

Homework Statement


Sketch the graph of the function y=(x-3)^2 by transforming the graph of an appropriate function of the form y=x^n

Homework Equations



y=(x-3)^2, y=x^n

The Attempt at a Solution


Precisely speaking, I am just totally confused with what the question is asking. i mean i know how to graph y=(x-3)^2 bit idk what the y=x^n is about. thanks so much!
 
Physics news on Phys.org
frozenbananas said:
im just totally confused with what the question is asking. i mean i know how to graph y=(x-3)^2 bit idk what the y=x^n is about. thanks so much!
They asked you how to transform graph of y=x^2 function to graph of y=(x-3)^2 function.

regards
 
Last edited:
They want you to start up with graph of y=x^2 and get y=(x-3)^2, which is just shifted in x axis.
 
n.karthick said:
They want you to start up with graph of y=x^2 and get y=(x-3)^2, which is just shifted in x axis.

but it says y=x^n so how did u get x^2? not to sound whiny, just confused?
 
You have to choose the value of n. In order to get the given function from y=x^n, the value of n has to be taken as 2.
 
k thanks ;)
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Back
Top